"if a train is travelling 30 mph and the train is 9300 foot long, how long will it filch to go past?"?




Answers:    Trains that long are available. BNSF runs one intermodal a week out of california that is 10,000 foot long. It is DP'd.

They tried a 200 car coal train, but have the "same/opposite" switch the wrong way and ripped the train surrounded by half. <chief end power> .. <cars> .. <mid train power> .. <cars> .. <backside end power>

The problem beside long trains is not the ability to do it, but convincing the conductor to put your foot back 1.5 miles to cut the crossing because you will not fit anywhere.

If the quiz is whether it is passing a set point, or whether it is clearing a tunnel (or other restriction that will raison d`¨ētre it to go 30 mph) as you would hold to go one and the same speed through the entire tunnel.

If for instance your train was going twice as vigorous (30 x 2 = 60) then it would cover one mile surrounded by one minute. 60 miles per hour, 60 minutes in an hour 60 = 60.
Then the following statement would be true.
1 mile = 2 minutes (at 30 mph)
5,280 foot in a mile, and 120 second in 2 minutes, so
5280 foot = 120 seconds (divide by 2)
2640 foot = 60 seconds (in one minute you will travel 2640 feet)
Take the total length of the train (9,300 feet), and divide by the distance that the train travels surrounded by one minute (2,640 feet).

9300/2640 = 3.522

It would take 3.522 minutes or approximately 3 min 30 second (.522 is approximately half of 1.000, and 30 second is half of one minute)
dude, do your own homweork
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