Mark drove 250 mi to visit Sandra. Returning by a shorten route, he found that the trip be only 225 mi, but traffic slowed his speed by 5 miles. If the two trips took exactly matching time, what was his rate on the return trip?
Answers: You obligation to ignore the wording and concentrate on facts.
distances are 250 & 225. Time be the same, so cut it. The variable is speed, so we give the name it x
This gives us the formula, which we solve for x:
250x-225(x-5) = 0
250x-225x-1125 = 0
25x = 1125
x = 45
This give us the original trip speed. The return trip be 5 mph slower, so it is 40 mph.
First, I need to know how hasty Mark was going (MPH)? I can not answer the request for information without that info.
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