6(5k-8)-20=11(2k-3)+3k?

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Answers:    6(5k-8) - 20 = 11(2k-3) + 3k

Distribute the 6 on the left side and distribute the 11 on the right side.
30k - 48 - 20 = 22k - 33 + 3k

Combine approaching terms on respectively side
30k - 68 = 25k - 33

Subtract 25k from each side.
5k - 68 = -33

Add 68 to respectively side
5k = 35

Divide both sides by 5.
k = 7

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k = 7

lol

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